I can think of lots of inelegant ways to access the outermost path of a glyph with many nested paths via scripting, but is there an elegant way?
If you can rely on it beingthe first path (as it should), it is simply:
If you can rely on it being the one with the largest bounding box (should always be true, right?):
largestBBox = 0 outermostPath = None for path in Layer.paths: size = path.bounds.size bbox = size.height * size.width if bbox > largestBBox: largestBBox = bbox outermostPath = path if outermostPath: Layer.clearSelection() for node in outermostPath.nodes: Layer.selection.append(node)
I would iterate all path/node and get the node with the smaller x value. That path has to be an outermost.
Does the lowest path when drawn automatically slot in at the paths spot?
If not,would a
correctPathDirection() fix it, and thus be useful before Layer.paths?